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![Peter Tram](https://secure.gravatar.com/avatar/2866065f24a57d85370c0103127cdd6c?s=96&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Peter Tram
Courses Plus Student 6,898 PointsThis code should work. Why do I receive a Bummer message?
d
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(string):
string = string.lower()
string = string.split(" ")
word_count_dict = {}
for word in string:
if word in word_count_dict.keys():
word_count_dict[word] += 1
else:
word_count_dict[word] = 1
return word_count_dict
2 Answers
![Stuart Wright](https://uploads.teamtreehouse.com/production/profile-photos/6368232/micro_footgolf.jpg)
Stuart Wright
41,119 PointsYou just need to make one small edit to pass the challenge:
string = string.split()
The .split() method by default will split on all whitespace characters, which is slightly different from what your code does. For example, your code won't split on tabs or newline characters.
![Peter Tram](https://secure.gravatar.com/avatar/2866065f24a57d85370c0103127cdd6c?s=96&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Peter Tram
Courses Plus Student 6,898 PointsThanks Stuart!