JavaScript JavaScript Basics Creating Reusable Code with Functions Passing an Argument to a Function

This hurts. I can't figure this out at all.

I'm still stuck on this return function problem. I did 2 of the 3 tasks but the main problem I'm having is the whole 'return passed in' code. The parameters I have tried are the var echo = return Value ( ); returnValue = value; and returnValue (''); as well as

script.js
function returnValue( value ) {
    var value = Math.floor( Math.random() * value ) + 1;

}

var echo = returnValue (''):
index.html
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

4 Answers

Simon Sporrong
Simon Sporrong
34,326 Points

As KRIS NIKOLAISEN wrote, you just have to :

return value;

So what's happening here is that you are creating a function that accepts one argument/parameter. All that the function does is returning that value. So you use the keyword return and then the name of the parameter. In this case: value. Hope it helps!

Thank you. I finally figured it out by starting over and fixing that. :3 Luckily it was still in the same parameter and I (value); where I thought I needed a math parameter. But thank you.

I know there's something I'm missing, I even viewed the video twice to make sure I get it down right.

KRIS NIKOLAISEN
PRO
KRIS NIKOLAISEN
Pro Student 50,933 Points

The third task may be simpler than you think. You are just supposed to return the value passed in:

function returnValue(value) {
    return value;
}

to finish my statement, I even tried return true and return false else parameters.