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Benjamin Bradshaw
3,208 PointsThis is a hard challenge.
I don't feel I have been given the tools to figure this one out. My code looks super sloppy and there has to be a simpler way of writing this. I feel absolutely stumped
# EXAMPLES:
# move((1, 1, 10), (-1, 0)) => (0, 1, 10)
# move((0, 1, 10), (-1, 0)) => (0, 1, 5)
# move((0, 9, 5), (0, 1)) => (0, 9, 0)
def move(player, direction):
x, y, hp = player
if direction == (-1,0):
x -= 1
elif direction == (1,0):
x += 1
elif direction == (0, -1):
y -= 1
else direction == (0, 1):
y += 1
if x >= 9:
x -= 1
hp -= 5
elif x <= 0:
x += 1
hp -= 5
elif y >= 9:
y -= 1
hp -= 5
else y <= 0:
y += 1
hp -= 5
return x, y, hp
1 Answer
Steven Parker
229,732 PointsWhat about diagonal movement?
The instructions don't actually say if there are limits to movement either in direction or distance. So you might want to calculate the potential new position using both dimensions, and then check to see if it is to a valid point. This could help make your code much more compact as well.
Also remember that both 0 and 9 are valid positions in both dimensions.