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This is a Javascript question that I'm learning from code academy. Help me please

Here are the instructions:

```Print out the numbers from 1 - 20.
The rules:
For numbers divisible by 3, print out "Fizz".
For numbers divisible by 5, print out "Buzz".
For numbers divisible by both 3 and 5, print out "FizzBuzz" in the console.
Otherwise, just print out the number.
```

Why does this not work?

```var numbers = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]

for ( x=1; x < numbers.length; x++) {
switch(numbers) {
case ( numbers % 3):
console.log("Fizz");
break;
case (numbers % 5):
console.log("Buzz");
break;
case (numbers % 3 && numbers % 5):
console.log("FizzBuzz");
}
console.log(numbers);
}
```

Hi Gary,

You cannot use a switch for this exercise. A switch evaluates a expression and depending on the result (case), executes a piece of code.

You can use something like this though:

```var numbers = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]

for ( x=0; x < numbers.length; x++) {
if( numbers[x] % 3 == 0 && numbers[x] % 5 == 0)
{
console.log('FizzBuzz ' + numbers[x]);
}else if( numbers[x] % 5 == 0){

console.log('Buzz ' + numbers[x]);

}else if ( numbers[x] % 3 == 0){

console.log('Fizz ' + numbers[x]);
}
}
```

I tired using this and it says "Oops, try again. It looks like you printed out the wrong number of items."

This is just a guide for your exercise, it is not the full answer. Try it like this:

```var numbers = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]

for ( x=0; x < numbers.length; x++) {
if( numbers[x] % 3 == 0 && numbers[x] % 5 == 0)
{
console.log('FizzBuzz ');
}else if( numbers[x] % 5 == 0){

console.log('Buzz ');

}else if ( numbers[x] % 3 == 0){

console.log('Fizz ');
}
else{
console.log(numbers[x]);
}
}
```

Oh I see I had to take out the + numbers[x]. Thank you so much. I was stuck on that for days. How did you get so good at Java Script? Seriously? Its been 3 months and I'm still struggling. How can I develope some serious skills?

Like most skills its all about repetition, I've been coding for years and there is still lots of things to learn. Just keep going.