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JavaScript

Posted by Oleg Kuperman
Oleg Kuperman
2,188 Points

This is a question based on the teacher's notes.

The script shows - Example: loop that runs 10 times

var counter = 1;
while (counter <= 10) {
    console.log(counter);
    counter += 1;
}

Now, when running this in the console, I get the number 1 - 11. With the 11th number not showing a debugger link next to it. Can someone explain why I'm seeing this?

VM96:3 1 VM96:3 2 VM96:3 3 VM96:3 4 VM96:3 5 VM96:3 6 VM96:3 7 VM96:3 8 VM96:3 9 VM96:3 10 11

1 Answer

andren
andren
28,558 Points

The loop itself only prints out the numbers 1 to 10. But the console is setup to automatically print out the return of the last command performed. Since the last operation performed is counter += 1 which returns 11 that is also printed out.

Since it is technically not something the code itself printed out it does not have any debug info associated with it. You could remove the console.log line from the code entirely and you would still get 11 printed out if you ran the code.