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CSS CSS Basics (2014) Enhancing the Design With CSS Gradients

this only say answer no longer passing. im not seeing anything wrong.

i might be missing something small, but ive tried this with the deg, and with "to bottom", and website wont pass this asnwer.

style.css
.main-header {
    background-image: linear-gradient (180deg, steelblue, darkslateblue 90%);
}
index.html
<!DOCTYPE html>
<html>
  <head>
    <title>Lake Tahoe</title>
    <link rel="stylesheet" href="page.css">
    <link rel="stylesheet" href="style.css">
  </head>
  <body> 
    <header id="top" class="main-header">
      <span class="title">Journey Through the Sierra Nevada Mountains</span>
      <h1 class="main-heading">Lake Tahoe, California</h1>
    </header>

        <div class="primary-content">
            <p class="intro">
                Lake Tahoe is one of the most breathtaking attractions located in California. It's home to a number of ski resorts, summer outdoor recreation, and tourist attractions. Snow and skiing are a significant part of the area's reputation.
            </p>
            <a class="callout" href="#more">Find out more</a>
        </div><!-- End .primary-content -->
  </body>
</html>
Dave StSomeWhere
Dave StSomeWhere
19,870 Points

Have you tried removing the space between the t in gradient and the opening parenthesis? So it would be:

.main-header {
    background-image: linear-gradient(180deg, steelblue, darkslateblue 90%);
}

2 Answers

Hey! If you substitute the degrees with a 'to top' instead, it should let you pass.

Good luck!

A value of 180deg is equivalent to to bottom . Since the challenge is asking you to set the gradient direction from bottom to top, you should use either 0deg or to top.