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This return task question is too vague im not sure what it asking. it says square but is not defined but is printed.......

squaring.py
```def square(number):
return square(number**)
``` Hi Carlos,

The question wants you to write a function called `square` that takes a number (`number`) and then returns a value that is the square of that number (i.e., that number multiplied by itself).

There are a couple of ways you can compute the square, for example you could use the multiplication operator (`*`) to multiply number by number. Or, you could use the the exponentiation operator (`**`) to raise number to the power 2. When using either of these operators they take the form `a <operator> b`, so, for example, multiplying 3 and 4 would be `3 * 4` or raising 6 to the power 3 would be `6 ** 3`.

Once you have calculated the value, you just return it. In your current code you have created an infinitely recursive function (calling square inside square) that never actually returns a value it just keeps calling itself until the recursion depth limit is reached, at which point the application will crash.

Hope that clears everything up.

Cheers

Alex