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Jassim Alhatem
20,883 PointsThis suddenly happened to both of my codes.
I need help with this i have no idea how to fix i spent 2 hours on it none stop and it wouldn't work.
trys = 1
h = ["warrior","cook","horseman","RoyalGaurd","Hunter","Murderer","Archer","SpearMan"]
print(h)
name = input("type in the number of the word that does not fit in... ")
while name != "2":
if trys > 3:
sys.exit("Sorry out")
trys += 1
name2 = input("try again... ")
if name2 == "2":
print("correct!")
del h[1]
print(h)
break
else:
print("correct!")
del h[1]
print(h)
I dont want to use break but i had to, because it keeps repeating if i dont. can someone help?
and it says try again like 6 times and i only want to say it 2 times.
thank you so much.
Jassim Alhatem
20,883 Pointsthats my 2nd code
import sys
#While loops
PASS = "CrasMeat"
Trys = 2
Password = input("Please enter your Password.. \n ")
while Password != PASS:
if Trys > 3:
sys.exit("sorry too many invalid attempts")
Ra = input("invalid Password please try again.. \n ")
Trys += 2
if Ra == PASS:
print("Welcome Abada")
else:
print("Welcome Abada")
****The Outcome is for the 2nd attempt, ( thats what Im struggling on on both codes): Please enter your Password..... **For example....crasmeat invalid Password please try again... CrasMeat Welcome Abada sorry too many invalid attempts..
that line above is the one that is annoying me. thank you.
2 Answers
Alex Koumparos
Python Development Techdegree Student 36,886 PointsHi Jassim,
Let's walk through your program (the second attempt you described).
We'll start the program, so Trys is initially set to 2, and when it first asks us for a password, let's enter python. Thus python gets assigned to the Password variable.
python is not CrasMeat so we enter the while loop.
Trys is less than 3, so we don't trigger sys.exit.
Now we get asked for the password again, so let's now enter CrasMeat. This time, the password we entered gets saved to the Ra variable and not to the Password variable (which is still python).
Trys gets increased by 2, so is now 4.
Ra (CrasMeat) is equal to PASS so we print the welcome message.
Since Password is still python, the loop goes round again.
Trys is 4 which is > 3 so we trigger the "too many invalid attempts" message and trigger sys.exit.
You didn't describe exactly how you wanted or expected your program to behave, and there was no link to a challenge, so I can't tell you how to get from where you are to where you want to be, but hopefully this step by step was clear enough to give you a hint for whatever change you need to make.
Cheers
Alex
Jassim Alhatem
20,883 PointsThank you so much Alex! Here is what i changed...
PASS = "CrasMeat"
Trys = 1
Password = input("Please enter your Password.. \n ")
while Password != PASS:
if Trys > 3:
sys.exit("sorry too many invalid attempts")
Password = input("invalid Password please try again.. \n ")
Trys += 2
else:
print("Welcome Abada")
Darren Harrison
Courses Plus Student 5,126 PointsJust a quick look in the first code shows a variable name and name2...these are not the same...the while loop uses name and you introduce name2 later...I think this is why you have to use break. Change name2 to name and you shouldn't have to use break...I think.
Hope this helps! Darren
Jassim Alhatem
20,883 Pointsohhhh thanks @DarrenHarrison
Jassim Alhatem
20,883 PointsJassim Alhatem
20,883 Pointsand another note, i had to break it because it will print out sys.exit("sorry out")