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George Clement
2,816 Pointsthis works for me but it says the app is getting the wrong output
kinda strange
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(the_phrase_to_parse):
the_phrase_in_lower = the_phrase_to_parse.lower()
the_phrase_to_in_list = the_phrase_in_lower.split(" ")
storage_dic = {}
for _ in the_phrase_to_in_list:
if _ in storage_dic:
storage_dic[_] = storage_dic[_] + 1
else:
storage_dic[_] = 1
return storage_dic
1 Answer
Jennifer Nordell
Treehouse TeacherHi there, George Clement ! First, you're doing terrific and you are far from the first to be stumped by this. Would you believe that the problem lies partially between your test data and the interpretation of the instructions? The instructions say you should split on all whitespace. This includes things like tabs and newlines. But if I were a betting woman, I'd bet that your test data didn't contain any tabs or newline characters, so you got back exactly what you would expect. The reason for this is that you are splitting only on spaces.
This splits on spaces:
split(" ")
But this splits on all whitespace:
split()
Simply removing the " " from the arguments in the split() causes this to pass with flying colors!
Hope this helps!
