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Start your free trialJames Montgomery
5,182 PointsThis works in a regular environment...
This works as designed, but I cannot get it to pass the browser test.
COURSES = {
"Python Basics": {"Python", "functions", "variables",
"booleans", "integers", "floats",
"arrays", "strings", "exceptions",
"conditions", "input", "loops"},
"Java Basics": {"Java", "strings", "variables",
"input", "exceptions", "integers",
"booleans", "loops"},
"PHP Basics": {"PHP", "variables", "conditions",
"integers", "floats", "strings",
"booleans", "HTML"},
"Ruby Basics": {"Ruby", "strings", "floats",
"integers", "conditions",
"functions", "input"}
}
def covers(item):
course_list = []
for k, v in COURSES.items():
if item.issubset(v):
course_list.append(k)
return course_list
2 Answers
Steven Parker
231,269 PointsThis does something a bit different from what the instructions ask for. They want a list of every overlap, not just complete subsets. An "overlap" would be any case where the intersection was non-empty.
You might want to keep this idea in reserve though .. it could be handy for the next task.
James Montgomery
5,182 PointsAh, yes. Thank you! intersection has done the trick and the next challenge - well that's solved ;)