Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Dates and Times in Python (2014) Dates and Times Timedelta Minute

timedelta

I understand what the question is asking here, I don't have an idea of how to approach the question. I started a for loop since the function takes multiple time deltas, so we need to retrieve seconds from both, matter of how is my first issue. After that I understand we are subtracting the greater from smaller, then results need to be rounded up to minutes but how can I separate the two so it subtracts correctly old from new and not the other way around??? .

minutes.py
def minutes(datetimes):
    for item in datetimes:
      item.timedelta.total_seconds() - item.timedelta.

1 Answer

Steven Parker
Steven Parker
229,645 Points

I think you misunderstood the instructions — this function will always take two arguments and use them to make one calculation. So you won't need a loop.

Also the instructions explicitly say "The first will always be older and the second newer. You'll need to subtract the first from the second.", so you won't have to handle it "the other way around".