Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
Nicole A
1,790 Pointstimedelta
Could someone please tell me how to write the code such that the arguments entered in the time_machine function can be used in the timedelta e.g if string, integer == days, 5, the timedelta should be days = 5.
import datetime
starter = datetime.datetime(2015, 10, 21, 16, 29)
def time_machine(string,integer):
from datetime import timedelta
return starter + timedelta()
# Remember, you can't set "years" on a timedelta!
# Consider a year to be 365 days.
## Example
# time_machine(5, "minutes") => datetime(2015, 10, 21, 16, 34)
1 Answer
Steven Parker
230,274 PointsIf you check the Python online documentation for timedelta Objects, you'll see that you can construct one by passing an argument indicating the offset. So for your example (and without any additional imports): datetime.timedelta(days=5). Since your method will receive both the unit name and quantity as arguments, you can use those parameters to
select or build the correct statement to use.
The only other trick is that your method needs to handle "years", but since that's not one of the standard offset units some conversion will be required.
Nicole A
1,790 PointsNicole A
1,790 PointsThank you for taking the time out to explain this Steven.