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Python Dates and Times in Python Dates and Times Timedelta Minute

timedelta minuite

What I'm doing wrong here? can anyone please tell me what this 'round' does ??

import datetime
def minutes(datetime1,datetime2):
    datetime1 = datetime.timedelta.total_seconds(datetime1)
    datetime2 = datetime.timedelta.total_seconds(datetime2)
    diff_in_min = (datetime1 - datetime2)/60
    return round(diff_in_min)

2 Answers

Chris Freeman
Chris Freeman
Treehouse Moderator 67,464 Points

You are on the right track, here are some hints:

  • be mindful when subtracting. datetime2 is the “later” time and therefore has the larger epoch time
  • the total_seconds method is only available on the timedelta object: (datetime2 - datetime1)

    • 👉 (datetime2 - datetime1).total_seconds() is legal syntax but you may wish to assign the subtraction to a variable, then call the method on that variable.
  • the first and second statements reassigning datetime1 and datetime2 are not necessary. (I commented them out

Post back if you need more help. Good luck!!!

Thank you for the response. It helped me to solve the problem.