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Python Dates and Times in Python (2014) Dates and Times Timedelta Minute

Posted by Guy-Francis Kono
Guy-Francis Kono
9,289 Points

Time-Stuck...

Can someone please help me with this challenge? I can't seem to make head-ways with this no matter how I try it...

minutes.py 
import datetime


time_record_1 = datetime.datetime.today() - datetime.timedelta(hours=2)
time_record_2 = datetime.datetime.today()

def minutes(time_record_1, time_record_2):
    time_diff = time_record_2 - time_record_1
    print(datetime.timedelta.total_seconds(time_diff))

1 Answer

Steven Parker
Steven Parker
229,732 Points
Steven Parker
Steven Parker
229,732 Points

:point_right: It looks like you have three issues:

  • The challenge asked for the result in minutes, not seconds (you'll need to convert)
  • The challenge also asked for the result to be rounded
  • You need to return the result, not print it

Also, while it doesn't hurt anything, the two variables you defined above the function are not used (and not necessary).

Guy-Francis Kono
Guy-Francis Kono
9,289 Points

Hi Steven. Thank you for helping out.

I attempted to convert the seconds to minutes by dividing the hours by dividing the seconds by 60, rounding by using the .round() function, and replacing print() with return. However I do not get the right answer. Do you have any other tips to improve this?

Thank you

import datetime


time_record_1 = datetime.datetime.today() - datetime.timedelta(days=63)
time_record_2 = datetime.datetime.today()

def minutes(time_record_1, time_record_2):
    time_diff = time_record_2 - time_record_1
    time_diff_min = (datetime.timedelta.total_seconds(time_diff)) / 60
    return time_diff_min.round(0)