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Android Build a Simple Android App (2014) Testing and Debugging Making a Toast

Bob Boursaw
Bob Boursaw
2,047 Points
Posted by Bob Boursaw
Bob Boursaw
2,047 Points

Toast.makeText(this, "All done!", Toast.LENGTH_LONG).show(); No idea why this doesn't work.

I am apparently missing something from the course, but I don't understand what it is and have tried about 10 different variants of the code, all failing.

ToastTest.java 
Toast allDoneToast;
allDoneToast = Toast.makeText(this, "All done!", Toast.LENGTH_LONG).show();

2 Answers

EVGENII MAMONTOV
EVGENII MAMONTOV
7,666 Points
EVGENII MAMONTOV
EVGENII MAMONTOV
7,666 Points

I think you've got incompatible types in your left and right sides of the equation. Toast.makeText(this, "All done!", Toast.LENGTH_LONG) - is the "Toast" type, great. But Toast.makeText(this, "All done!", Toast.LENGTH_LONG).show() returns nothing, it's "void", and cannot be equal to allDoneToast variable of the"Toast" type. Try breaking your operator into two: allDoneToast = Toast.makeText(this, "All done!", Toast.LENGTH_LONG); allDoneToast.show();

Alex Johnson
Alex Johnson
6,067 Points
Alex Johnson
Alex Johnson
6,067 Points

This helped me. Thanks!

Alex Johnson
Alex Johnson
6,067 Points
Alex Johnson
Alex Johnson
6,067 Points

Update: Turns out that the reason you don't need a variable is because it's a static function of the Toast class so you can call it right from the class without instantiation.

I'm not sure why this didn't work in part one of the challenge, but to pass part three I was able to combine the first two lines into one without referencing a specific variable. This is what I put:

Toast allDoneToast = Toast.makeText(this, "All done!", Toast.LENGTH_LONG);
allDoneToast.show();
Toast.makeText(this, "Second toast!", Toast.LENGTH_LONG).show();