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# Too complicated

time_machine.py
```import datetime

starter = datetime.datetime(2015, 10, 21, 16, 29)

# Remember, you can't set "years" on a timedelta!
# Consider a year to be 365 days.

## Example
# time_machine(5, "minutes") => datetime(2015, 10, 21, 16, 34)

def time_machine(num, st):
```

Hi Ronit,

Remember that a timedelta object represents a duration, the difference between two dates or times.

see my solution below.

You can find extensive discussions on this here

```import datetime

starter = datetime.datetime(2015, 10, 21, 16, 29)

# Remember, you can't set "years" on a timedelta!
# Consider a year to be 365 days.

## Example
# time_machine(5, "minutes") => datetime(2015, 10, 21, 16, 34)

def time_machine(my_integer, my_string):
if my_string == 'minutes':
return starter + datetime.timedelta(minutes=my_integer)
elif my_string == 'hours':
return starter + datetime.timedelta(hours=my_integer)
elif my_string == 'days':
return starter + datetime.timedelta(days=my_integer)
elif my_string == 'years':
return starter + datetime.timedelta(days=my_integer * 365)

# print(time_machine(my_integer=5, my_string='hours'))
```

Give a man a fish and you feed him for a day; teach a man to fish and you feed him for a lifetime.
Â  Â  â€• Maimonides

You are right to say complicated. All the time the challenges had needed simple reasoning, and a few lines of code. This one needs you to evaluate inputs based on the arguments of your time_machine function.

If the string arg is minutes do this.. if the string arg is days do this...

This one passed it for me, its just telling the program to calculate the neccessary time to be added using the right unit of time. Remember the timedelta() method only accepts three arguments and these are days, seconds and microseconds. This is the Link (https://docs.python.org/3/library/datetime.html?highlight=timedelta#datetime.timedelta)

I wrote it like this;

''' python

def time_machine(integer,string):

```if string.upper() == 'MINUTES':
new_int = integer * 60
new_date = starter + datetime.timedelta(seconds=new_int)
return new_date

elif string.upper() == 'HOURS':
new_int = integer * 3600
new_date = starter + datetime.timedelta(seconds=new_int)
return new_date

elif string.upper() == 'DAYS':
new_int = integer
new_date = starter + datetime.timedelta(days=new_int)
return new_date

elif string.upper() == 'YEARS':
new_int = integer * 365
new_date = starter + datetime.timedelta(days=new_int)
return new_date

return new_date
```

'''