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JavaScript JavaScript Foundations Strings Methods

Jacob Tennyson
Jacob Tennyson
6,240 Points

toUpperCase

this "toUpperCase" code isnt working on my the test.

   var quick = "The quick brown fox jumps over the lazy dog";

          var quickLength    = quick.length;
          console.log(length);
          var indexOfBrown = quick.indexOf("brown");
          console.log(indexOfBrown);
          var tenthCharacter = quick.charAt(9);
          var wordBrown = quick.substr(10,5);
          console.log(quick);
          var quickUpper = quick;
          console.log(quick.toUpperCase());
          var quickLower = quick;
index.html
<!DOCTYPE html>
<html lang="en">
  <head>
    <title> JavaScript Foundations: Strings</title>
    <style>
      html {
        background: #FAFAFA;
        font-family: sans-serif;
      }
    </style>
  </head>
  <body>
    <h1>JavaScript Foundations</h1>
    <h2>Strings: Methods</h2>
    <script>
      var quick = "The quick brown fox jumps over the lazy dog";

          var quickLength    = quick;
          var indexOfBrown = quick;
          var tenthCharacter = quick;
          var wordBrown = quick;
          var quickUpper = quick;
          var quickLower = quick;
    </script>
  </body>
</html>

1 Answer

Herb Bresnan
Herb Bresnan
10,658 Points

Jacob, I don't think its necessary to log every thing to the console. He just wants to see if you know how objects work with methods. Remember: object.method();
The object you want to perform the method on is quick
You separate the object from the method with a "." And the method you are using is toUppercase();
var quickUpper = quick.toUpperCase();