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# Transposing my array?

I am a novice programmer in python and was wondering if I can get a little help. The code I am about to show below prints out a simple array based on the users input for # of rows and # of columns.

```new_list = []

undersc = '_'

for i in range(1, rows + 1):

new = []

for j in range(1, columns + 1)

new.append(undersc if j > i else 'Z')

new_list.append(new)

for c in range(len(new_list[0])):

print()

for r in range(len(new_list)):

for c in range(len(new_list[0]))

array = print((new_list[r][c]), end=" ")

print()

return array
```

The console outputs the following:

```Z _  _  _  _

Z  Z  _  _  _

Z  Z  Z   _  _
```

I am completely lost as to how I would transpose my array in other words swap the columns with the rows. Any help would be greatly appreciated!

MOD

You have all the information you need. To reverse the columns and rows exchange your inner and outer loops:

```# initial print loop
for r in range(len(new_list)):
for c in range(len(new_list[0])):
array = print((new_list[r][c]), end=" ")
print()

# transposed print loops
for c in range(columns):
for r in range(rows):
array = print((new_list[r][c]), end=" ")
print()
```

Compressing and cleaning up your code a bit:

```def array2(rows, columns):
new_list = []
undersc = '_'

# i and j are relative counters, no need to use 1-based counting
for i in range(rows):
new = []
for j in range(columns):
new.append(undersc if j > i else 'Z')
new_list.append(new)

# this prints out many blank lines. Not clear why it's needed
# for c in range(len(new_list[0])):
#     print()

for c in range(columns):
for r in range(rows):
# print does not return object, assignment to 'array' not needed
print((new_list[r][c]), end=" ")
print()

# no value being returned, explicit 'return' not needed
# return array
```

Produces:

```>>> array2(3, 4)
Z Z Z
_ Z Z
_ _ Z
_ _ _
```