tried everything but in vain

Question

Wow, I just can't stump you! OK, two more to go. I think this one's my favorite, though.

Create a function named most_courses that takes our good ol' teacher dictionary.

most_courses should return the name of the teacher with the most courses. You might need to hold onto some sort of max count variable.

teachers.py

# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
#  'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers(tree_dict):
    intr = len(tree_dict)
    return intr
def num_courses(tree_dict):
    values = list(tree_dict.values())
    count = 0
    for item in values:
        for i in item:
            count += 1
    return count
def courses(tree_dict):
    final_list =[]
    values = tree_dict.values()
    for item in values:
        for i in item:
            print(i)
            final_list.append(i)
    return final_list
def most_courses(tree_dict):
    value_list = []
    key_list = []
    for item in tree_dict.values():
        value_list.append(item)
    for item in tree_dict.keys():
        key_list.append(item)
    if len(value_list[0]) > len(value_list[1]):
        return key_list[0]
    elif len(value_list[0]) < len(value_list[1]):
        return key_list[1]
    else:
        return (key_list[0], key_list[1])

Answer 1 · 2018-05-15T23:14:14Z

May 15, 2018 11:14pm

Here's a few hints:

you don't need to create any additional lists
you should only need one loop
you've already counted courses in "num_courses"
this time, you can do something similar but also keep track of the highest count (and associated teacher)
after checking them all, return only the name of the teacher that had the most courses

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Siddharth Pande

Siddharth Pande

tried everything but in vain

1 Answer

Steven Parker

Steven Parker