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marcolamoon
16,915 PointsTried everything i could think of...HELP!
Create a function called "reverse_text" that takes a string as an argument, and returns a string with those words reversed. So reverse_text("balloon") should return "noollab".
from django import template
register = template.Library()
def reverse_text(agr):
return template("noollab")
4 Answers
Carlton M Mandikiyana
7,836 Pointsdef reverse_text(string): return string[::-1]
this will pass the challenge
Steven Parker
229,732 PointsThe challenge is only telling you that reverse_text("balloon") should return "noollab" as an example.
You should not assume what actual argument will be given, and your function should create the output by using the argument and performing a process on it that will give the desired result.
marcolamoon
16,915 Pointsi did the following code and its not working.
from django import template
register = template.Library()
def reverse_text(balloon): return "noollab"
Steven Parker
229,732 PointsYou're still returning a fixed string that would only be the proper response if the function was called with "balloon" as an argument. But what if it was called with "widget" or "jabberwock?
You need to compute a reversed version of the argument so the answer will be correct no matter what the input is.
wisdom mapeka
25,213 Pointshow Did you solve this one, I am facing a similar challenge ,
Steven Parker
229,732 PointsThere are a few ways to do this, one would be to use the "reversed" option on a loop.
But a slice with a negative step value is even easier.
Munyaradzi D Sabamba
8,310 Pointsyou should return the answer as below
def reversed_text("balloon"): return balloon[::-1]
it should pass the test
Steven Parker
229,732 PointsThat's what I was hinting at a year and a half ago. I was just trying to avoid giving away a "spoiler".