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Python Django Class-based Views Classy Views Basic View

Trouble passing Django generic Class View challenge. "Didn't find the URL for your view" . See what I'm missing?

I think my code is correct, but my URL is throwing an error. I don't see what I'm missing. I believe the import statement is correct and I thought the URL was correct, but evidently I'm missing something. I can't get past this challenge,

from django.conf.urls import url, include

from . import views 

urlpatterns = [
    url(r'^/', views.WelcomeView.as_view()),
from django.http import HttpResponse
from django.views.generic import View

class WelcomeView(View):
    def get(self, request):
        return HttpResponse("whatever")
Gregory Olsen
Gregory Olsen
8,515 Points

The question asks for the route to be '/'. for the url, just do an empty string to get the / route.

urlpatterns = [ url('', views.WelcomeView.as_view()), ]