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iOS Swift Functions and Optionals Parameters and Tuples Tuples

Posted by Thomas Katalenas
Thomas Katalenas
11,033 Points

trouble returning

func greeting(person:String) -> String{
    let language = "English"
    let greeting = "Hello \(person)"
    let tup = (greeting, language)
    print(tup)
    return greeting

}


greeting("tom")

I get the basic idea and this returns, ("Hello Tom", "English")

but I cant return (greeting, language) or I get this error

tmp/3wXV2YS6fa.m:8:12: error: cannot convert return expression of type '(String, String)' to return type 'String'

tuples.swift 
func greeting(person: String) -> String {
    let language = "English"

    let greeting = "Hello \(person)"
    let tup = (greeting, language)
    print(tup)
    return greeting
}

4 Answers

Anish Walawalkar
Anish Walawalkar
8,534 Points
Anish Walawalkar
Anish Walawalkar
8,534 Points

You're almost there. You just need to change your function definition to show that it is now going to return a tuple not a string. I also did the remaining part of the challenge:

so in code:

func greeting(person: String) -> (greeting: String, language: String) {
    let language = "English"
    let greeting = "Hello \(person)"

    return (greeting, language)
}

var result = greeting("Tom")

println(result.language)
Anish Walawalkar
Anish Walawalkar
8,534 Points
Anish Walawalkar
Anish Walawalkar
8,534 Points

don't know why the -> isn't showing up properly lol

Thomas Katalenas
Thomas Katalenas
11,033 Points
Thomas Katalenas
Thomas Katalenas
11,033 Points

oh I was wondering about that lol 

func greeting(person: String) -> (String,String) {
         let greeting = "Hello \(person)"
         let language = "English"
         let tup = (greeting, language)
         print(tup)
         return tup
}

like that?

Anish Walawalkar
Anish Walawalkar
8,534 Points
Anish Walawalkar
Anish Walawalkar
8,534 Points

Yeah thats perfect, just remove the print. also just a just a quick note:

func greeting(person: String) -> (greeting: String, language: String) {
         let greeting = "Hello \(person)"
         let language = "English"
         let tup = (greeting, language)
         print(tup)
         return tup
}

if you name your return values in the return tuple, like I have you can access them like this:

var result = greeting("Tom")
print(result.greeting)
print(result.language)

However if you do not name them, then you will have to access them like this:

var result = greeting("Tom")
print(result.0) //to print the greeting
print(result.1) //to  print the language

Hope that helps

Thomas Katalenas
Thomas Katalenas
11,033 Points
Thomas Katalenas
Thomas Katalenas
11,033 Points

is that faster, greeting("Tom").1

Anish Walawalkar
Anish Walawalkar
8,534 Points
Anish Walawalkar
Anish Walawalkar
8,534 Points

No, its takes the same time to execute (as far as I can tell)

Thomas Katalenas
Thomas Katalenas
11,033 Points
Thomas Katalenas
Thomas Katalenas
11,033 Points 
for i in 0..2{  //or stream of 1's and 0's 
    let a: int = i
    var m = greeting("John").a
    print(m)
}