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# Try again error

The code gives me the try again message. I cant find anything from my end. Anyone for the rescue please?

disemvowel.py
```def disemvowel(word):
word_list = list(word)
index = 0
while (word_list < len(word_list)):
if word_list[index] = "a" or word_list[index] = "e" or word_list[index] = "i" or word_list[index] = "o" or word_list[index] = "u":
del word_list[index]
elif word_list[index] = "A" or word_list[index] = "E" or word_list[index] = "I" or word_list[index] = "O" or word_list[index] = "U":
del word_list[index]
index = index + 1
return word
```

Hello

```you should be using == instead of =
```

Thanks Mark. I think that is part of the issue. I changed that and the error is now 'try again'. I know the logic is correct, but maybe some syntax I cant figure out.

Hello

Please take a look at this code ... please spend some time comparing to what you did. The ket part to realize is how this p2 lines

```for letter in word.lower():
if letter in vowels:

can replace a lot of the code writing you were doing:

def disemvowel(word):
new_word = word
vowels = ('a', 'e', 'i', 'o', 'u')
for letter in word.lower():
if letter in vowels:
new_word = new_word.replace(letter, "")
return new_word

print(disemvowel("abcdefghijklmopqrst"))
```

run the example with different strings using a conole or IDE

thanks

Hi! I am still stuck in this step. I tried the below code in the workspaces and it was bringing out the right result but in here it gives an error: 'got back the letters I wasn't expecting.

def disemvowel(word): vowels = ['a', 'e', 'i', 'o', 'u'] new = list(word.lower()) for letter in new: if letter in vowels: word = new.remove(letter) return word

Any assistance will be appreciated.