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# try and except 1/3

I don't understand why it won't return the values added together even though I have defined them as integers.

arg1 = 1

arg2 = 2

total = arg1 + arg2

my bad I thought it posted the code. Thank you for the help, I was able to figure it out.

I understand that you are having a problem with this challenge, as you have not specified which part exactly you are stuck on, I will explain each part of the challenge step by step.

```def add(a, b):
return a + b
```

This first task is simple, this function takes in 2 arguments which are integers. It adds them both together then returns the sum of them both.

In the second task, you have to convert the 2 arguments into floats before you add them. You can do this using the float() function. You can shorten this code by assigning both variables in one line. Either of the 2 solutions below will work:

```def add(a, b):
a = float(a)
b = float(b)
return a + b
```
```def add(a, b):
a, b = float(a), float(b)
return a + b
```

Finally, in task 3, we need to handle a situation where instead of 2 integers, something like a string is passed in. We need to try to convert both arguments to floats. However, if there is a ValueError, we should return the value None. You can do this with the following code, I will add comments to explain what each part does:

```def add(a, b):          #define function named add which takes 2 arguments
try:                #try to do the following:
a = float(a)
b = float(b)
except ValueError:  #If there is a ValueError
return None     #return None because this means either one or both of the arguments are not an integer
return a + b        #Finally, if there is no value error, add the two floats together and return the total
```

I hope i solved your problem and that you understand now!