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# try, except, else

I can't see what's wrong with my code? I'm checking if the argument is an int with type(num) == int. Is this the wrong way to do it?

Appreciate any help!

squared.py
```# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"

def squared(num):
try:
type(num) == int
except ValueError:
return num * len(num)
else:
return num * num
```

```def squared(num):
try:
int(num)
except ValueError:
return num * len(num)
else:
return int(num) ** 2
// or     return int(num) * int(num)
```

ahh I forgot to convert it , obvs... my type(num) == int syntax works like int(num) in the try block?

Well let me show you on IDLE:

```>>> int("1")
1
>>> int("test")

Traceback (most recent call last):
File "<pyshell#1>", line 1, in <module>
int("test")
ValueError: invalid literal for int() with base 10: 'test'
>>>
```
```>>> num = "test"
>>> type(num) == int
False
>>>
```

You get the difference ;)?

type() returns True or False while int() returns an integer (string converted to an int) or (what we need) an error-message

dont copy my comment Just to show you some other ways

```// or     return int(num) * int(num)
```

I get it, thanks Tobias! New to Python, learning it in order to build shopping system with stripe and django. Coming from beginner/intermediate level of Javascript, mostly angular!