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# Trying to take out every other item in a list.

I'm stuck writing a simple code that takes every other item out of an iterable and puts it in a new list. For example, in the string "abacadabra", I want to create "aaaar".

Here's what I've tried:

```word = 'abacadabra'
result = ''
for i in word:
if word.index(i) % 2 == 0:
result += i
print(result)
```

But instead of getting "aaaar", I get "aaaara".

With other words, I get varying results as far as which letters get left out or repeated depending on whether they appear elsewhere in the word. For example, with "xylophone", I get "xlpe" because the "o" appears in the odds (word.index(i) % 2 == 0 condition is not met and so the "o" gets left out when it is an index that DOES meet that condition.

So what am I missing and how what do I do to fix it?

Would I just have to use a dictionary?

It would probably be easier to not use modulo and just do i += 2 instead. This way you don't even need the if statement.

Sorry, not sure what that would look like. The i represents the character in the string, right? So it can't be incremented, can it?

And how would that look in the code?

Sorry! I just realized I used terminology from different programming languages. There are many ways to solving this problem, but I think the easiest to understand would be this:

```word = 'abacadabra'
result = ''
for i in range(0, len(word), 2):
result += word[i]
print(result)
```

Here, we turn the for-each loop into a for loop. We start at index 0, end at the length (count) of the string, and the third parameter shows that we increment by two (and thus skip every other) :)