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Start your free trialBenjamin Guyton
6,858 Pointstuplessss
I understand what the problem is asking for, and I feel like I'm heading in the right direction with the code I've written, but I'm stuck at what to do next. Any helpful advice available?
# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
def combo(my_list, my_string):
# create a list that will have tuples appended to it
tuples = []
count = 0
# create tuples containing the corresponding index to my_list and my_string
# loop through both arguments of combo()
for list_item in my_list and string_item in my_string:
return new_entry = (my_list[count], my_string[count])
count += 1
#return list of created tuples
return tuples.append(new_entry)
1 Answer
Steven Parker
231,269 PointsHere's a few hints:
- a "for" loop can only use one iterable
- a "for" loop with a range could generate index numbers
- you may want to append to the new list inside the loop
- you will not want to return until the loop is finished