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Python

Posted by Jonathan Kuhl
Jonathan Kuhl
26,133 Points

TypeError: __init__() got multiple values for argument 'sides'

As far as I can tell, I have the same code as Kenneth, but I keep getting this trace back error. TypeError: init() got multiple values for argument 'sides' I can't see what is causing this!

import random

class Die:

    def __init__(self, sides=2, value=0):
        if not sides >= 2:
            raise ValueError("Dice must have 2 or more sides!")
        if not isinstance(sides, int):
            raise ValueError("Sides must be of type int")
        self.value = value or random.randint(1, sides)

    def __int__(self):
        return self.value

    def __eq__(self, other):
        return int(self) == other

    def __ne__(self, other):
        return int(self) != other

    def __gt__(self, other):
        return int(self) > other

    def __lt__(self, other):
        return int(self) < other

    def __ge__(self, other):
        return int(self) > other or self == other

def __le__(self, other):
        return int(self) < other or self == other

class D6(Die):

    def __init__(self, value=0):
        super().__init__(self, sides=6, value=value)

1 Answer

Clayton Perszyk
MOD
Clayton Perszyk
Treehouse Moderator 49,041 Points
Clayton Perszyk
Clayton Perszyk
Treehouse Moderator 49,041 Points

try taking self out of init on this line: 

super().__init__(self, sides=6, value=value)

You might also need to add a couple arguments to the call to super.