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Paul Denlinger
2,380 Points"UIColor is not convertible to ()" error; cannot compile
Am getting two compilation errors with my code; they both say "UIColor is not convertible to ()" and won't let me compile.
Get one error on the
return colorsArray[randomNumber]
line in ColorWheel.swift, and the other error is on the showFunFact() method in the view controller:
@IBAction func showFunFact() {
var randomColor = colorWheel.randomColor()
view.backgroundColor = colorWheel.randomColor
funFactButton.tintColor = colorWheel.randomColor
funFactLabel.text = factBook.randomFact()
}
What is wrong?
6 Answers
Steve Hunter
57,712 PointsSorry for the delay, I'd gone out for a bit. Friday night & pub etc! I tried to answer your query on my phone but there's rubbish reception here in deepest, darkest Norfolk.
I think the issue you now have is that you have missed the parentheses from your method calls.
randomColor(); // brackets missing in your code
Sorry I didn't pick this up in your first post.
Steve.
Steve Hunter
57,712 PointsHi Paul,
Can you post the code for the randomColor method inside the ColorWheel class please?
It looks as though the method is returning a color instance but the method skeleton doesn't say it will do that. Just guessing at the moment until I can have a look at the code.
Post it all, if you want.
Steve.
Paul Denlinger
2,380 PointsHere you go:
func randomColor() {
var unsignedArrayCount = UInt32(colorsArray.count)
var unsignedRandomNumber = arc4random_uniform(unsignedArrayCount)
var randomNumber = Int(unsignedRandomNumber)
return colorsArray[randomNumber]
}
```swift
Steve Hunter
57,712 PointsYes - your func doesn't return anything in it's definition but then does in the method body.
You need to add -> UIColor in the header like:
func randomColor() -> UIColor {
Hope that works!!
Steve.
Paul Denlinger
2,380 PointsHi, thank you. I have added UIColor to the method signature for the randomColor method, but am still getting the same error for the showFunFact() method on lines 3, 4:
@IBAction func showFunFact() {
var randomColor = colorWheel.randomColor()
view.backgroundColor = colorWheel.randomColor
funFactButton.tintColor = colorWheel.randomColor
funFactLabel.text = factBook.randomFact()
}
```swift
Anthony Walker
4,448 PointsHas this question been answered as I too have the error. Everything works fine until the variable randomColor is created.
Removing the curly brackets to colorWheel. randomColor on both view.backgroundColor and funFactBytton.tintColor gives the error
function produces expected UIColor, did you mean to call it with '()'?
Steve Hunter
57,712 PointsHi Anthony,
I don't know what problem you're facing.
For starters, don't remove the brackets - they are essential for the methods you mention. ]
If you could post your code and let me know what errors you're getting, I'll have a look through and see if I can help you out.
Steve.
Anthony Walker
4,448 PointsIts ok I have code working. For the code above remove colorWheel from view.backgroundColor = colorWheel.randomColor and factFunButton.tintColor = colorWheel.randomColor
both these codes should read
view.backgroundColor = randomColor funFactButton.tintColor = randomColor
Why?
Because var randomColor is replacing all off colorWheel.randomColor()
Paul Denlinger
2,380 PointsPaul Denlinger
2,380 PointsHi Steve, That resolved the issue; thank you!