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iOS Swift 2.0 Basics Swift Types String Manipulation

Unable to get through String interpolation quiz

// Enter your code below Let name = "Abhinav" Let greeting = "Hi there" Let interpolatedString = "(greeting), (name)."

strings.swift
// Enter your code below
Let name = "Abhinav"
Let greeting = "Hi there"
Let interpolatedString = "\(greeting), \(name)."

1 Answer

Chase Marchione
Chase Marchione
155,055 Points

Hi Abhinav,

1) Swift is a case sensitive language, meaning that an uppercase letter and a lowercase letter are considered by the compiler to be different. So, to declare a constant, we'll need to type 'let' instead of 'Let'.

2) For this exercise, we are asked for the concatenated string to be the value of the greeting variable, rather than declaring a third variable.

// Enter your code below
let name = "Abhinav"
let greeting = "Hi there, \(name)."

Hope this helps!