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PHP PHP Basics (Retired) PHP Conditionals & Loops Conditionals Challenge

Tony Brackins
Tony Brackins
28,766 Points
Posted by Tony Brackins
Tony Brackins
28,766 Points

Under the variable $name create a if statement that test to see that the $name variable is set to the string 'Mike'.

Help!

This is what I have so far:

<?php $name = "Mike" if($name == "Mike"){ $info = 'Hi Mike'; } else{ $info = "Im not Mike" } ?>

5 Answers

Ken Alger
STAFF
Ken Alger
Treehouse Teacher
Ken Alger
Ken Alger
Treehouse Teacher

Tony;

There is an issue at the moment with the Treehouse challenge engine. They are aware of it and are working on it. See this post for additional information.

Ken

rosinapissaco
rosinapissaco
13,401 Points

Thanks. I have been trying it 10 times!

Elijah Collins
Elijah Collins
19,457 Points
Elijah Collins
Elijah Collins
19,457 Points

Tony Brackins not sure if you still need help, but here is what passed for me

<?php 

$name = "Mike";

if($name == "Mike") {
echo "Hi, I am " .  $name . "!";
}

?>
Ashenafi Ashebo
Ashenafi Ashebo
15,021 Points
Ashenafi Ashebo
Ashenafi Ashebo
15,021 Points

thank Elijah Collins, you saved my time.

Andres Altuve
Andres Altuve
16,274 Points
Andres Altuve
Andres Altuve
16,274 Points

Hi tony, the problem is you are testing your variable inside your variable.

Example:

<?php 

$name = "Mike";

 if ($name == "Mike") 

          echo "Hi Mike";   

        }else{

         echo "Im not Mike" ;}

?>



            ```
risetteshaw
risetteshaw
2,533 Points
risetteshaw
risetteshaw
2,533 Points

This worked for me:

<?php $name= "Mike"; if ($name == "Mike"){ echo 'Hi, I am Mike!'; }; ?>

Brandon Cleveland
Brandon Cleveland
11,134 Points
Brandon Cleveland
Brandon Cleveland
11,134 Points

You did not have a semicolon after ($name = "Mike")