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Python

Unexpected Syntax Error(except)

Getting a syntax error at line 18, couldn't figure out why. run the script a couple of times

import random 


def game():
    # generate a random number between 1 and 10
    secret_num = random.randint(1, 10)
    guesses= []

    while len(guesses) < 5: 
        try:
            # get a number guess from the player
            guess = int(input("Guess a number between 1 and 10: ")
        except ValueError:  <line 18> 
            print ("{} isn't a number!".format(guess))
        else: 

            # compare guess to secret number 
            if guess == secret_num:                
                 print ("You get it! My number was {}".format(secret.num)) 
                 break 
             else:
                 print ("That's not it!")
             guesses.append(guess) 
            # print hit/miss

 game()

[MOD: added ```python formatting -cf]

Christopher Janke
Christopher Janke
11,054 Points

guess = int(input("Guess a number between 1 and 10: ") is missing a )

is <line 18> in your code? Or are you just marking line 18 for the forum?

2 Answers

Abdishakur Hassan
Abdishakur Hassan
3,585 Points

You have this thing in your code next to exceptValueError <line 18> . Remove that and see if it works. And one More paranthesis is missimg before that in Guess=

Thanks guys... missed parenthesis was the issue now its resolved and "<line 18>" was for the forum