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JavaScript JavaScript Functions Pass Information Into Functions Function Parameters and Arguments

Posted by ja5on
ja5on
10,338 Points

upper and 6?

In this teaching video i dont see what upper and 6 are doing they seem irrelavent?

3 Answers

babyoscar
babyoscar
12,929 Points

Hi, upper is controlling how high the random number can be, by multiplying the result of Math.random() (which generates a random number between 0 and 1) by itself, then rounding the result down. That's basically the same as the first example where Math.random() was always multiplied by 6, except now you can change what it multiplies Math.random() by by changing the argument you pass in when you call the function. Hope this helped!

Peter Huang
Peter Huang
5,427 Points

god bless this comment. makes so much sense and I understand it more. thank you

ja5on
ja5on
10,338 Points
ja5on
ja5on
10,338 Points

Thanks for your answer, I kept reading it over and over... I found one sentence that in particular helped:-

PARAMETER VARIABLES ARE USED TO IMPORT ARGUMENTS INTO FUNCTIONS.

This sits printed out above my computer screens.

babyoscar
babyoscar
12,929 Points

No problem!

Team 2021
Team 2021
405 Points
Team 2021
Team 2021
405 Points

function getRandomNumber(upper) { const randomNumber = Math.floor(Math.random() * upper) + 1; return randomNumber; }

console.log(getRandomNumber(6));

why when passing 6, it generates a number lower than 6?

ja5on
ja5on
10,338 Points

6 is the value passed to the argument, the current limit of the program are from 1 - 6, and so the program wont go above 6, try submitting 100 instead of 6 and youll find it wont exceed 100!
console.log(getRandomNumber(100));