Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialGranit Berisha
14,150 PointsUse a for or while loop to iterate through the values in the temperatures array from the first item -- 100 -- to the las
Use a for or while loop to iterate through the values in the temperatures array from the first item -- 100 -- to the last -- 10. Inside the loop, log the current array value to the console.
var temperatures = [100,90,99,80,70,65,30,10];
for (var i = 0; i <= students.length; i += 1 ){
console.log(students[i]);
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>JavaScript Loops</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
5 Answers
alex gwartney
8,849 PointsYou need to take and remove students.length and replace that with temperatures.length and do the same for the console log swap out the students with temperatures and it should work just fine.
alex gwartney
8,849 Pointsvar temperatures = [100,90,99,80,70,65,30,10];
for(i=0; i<temperatures.length; i++){
console.log(temperatures[i])
}
Michael Humenick
1,138 PointsWhat does the "I++" mean?
claudius mainja
9,661 Pointswhy are you guys writting your code with the variable inside the for loop just like this var temperatures = [100,90,99,80,70,65,30,10];
for( var i=0; i<temperatures.length; i++){ console.log(temperatures[i]) }
Bradley Hapgood
Python Development Techdegree Student 10,854 Pointswouldn't it be better to use a For each loop instead?
John Norris
21,145 Pointsconst temperatures = [100, 90, 99, 80, 70, 65, 30, 10];
for (let i = 0; i < temperatures.length; i++) {
console.log(temperatures[i]);
}