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noel tanyanyiwa
6,877 PointsUse Console.WriteLine to print the contents of the firstName variable to the screen.
Task 2 of 3
string firstName = Console.ReadLine();
Console.WriteLine ("firstName");
2 Answers
Steven Parker
229,708 PointsNever put quotes around a variable name. That creates a string literal instead of referencing the variable.
Jared Williams
5,650 PointsWhat you are doing here is creating a string (a variable) named firstName in your program and setting it to whatever the user inputs. This part is correct.
The 2nd line is where you have trouble. You are not referencing the variable firstName you created on the previous line, but are instead passing in the string "firstName" instead of the variable. Basically your code will always print out "firstName", regardless of what the user types in. In order to print what the user types in, you need to use the variable firstName (without the quotes). This is the actual variable you stored the input in, not just some text in your code.
Jared Williams
5,650 PointsJared Williams
5,650 PointsTry giving more context by explaining what you are trying to do, and what your code is actually doing. This helps others make more intelligent comments and feel like you are invested in this question (and not just asking them to write your code for you). This applies not only to Team Treehouse comments, but anywhere online (stackoverflow.com) you may ask a question about coding.