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Start your free trialJulien Schmitt
2,334 PointsUse of unresolved identifier in func. Getting errors in xCode when reproducing what was done in iOS Dev Library.Why?
I read the iOS Dev Library on functions and I tried reproducing some of the functions listed there : https://developer.apple.com/library/ios/documentation/Swift/Conceptual/Swift_Programming_Language/Functions.html (the sayHello & sayHelloAgain)
I reproduced the exact same code in xCode however, I'm getting errors of unresolved identifier on my second function. Why ?
func sayHelloAgain(personName: String) -> String { let helloAgain = "Hello again, (personName)!" return helloAgain }
func sayHello(greetingsTo greetingName: String, alreadyGreeted: Bool) -> String { if alreadyGreeted { return sayHelloAgain(personName) <-- Use of unresolved identifier } else { return sayHello(greetingName) <-- Missing argument for parameter 'alreadyGreeting' in call. } }
I have a few questions here:
Why am I getting these errors (identifier & missing argument)?
When returning another function in a function, why can't we just put : return sayHelloAgain(personName: String) ?
Thanks for your help,
Julien
2 Answers
Anjali Pasupathy
28,883 PointsFirstly, in the sayHelloAgain function, you need a backward slash before the open parentheses to correctly use string interpolation:
let helloAgain = "Hello again, \(personName)!"
secondly, you need to put greetingName in the call to sayHelloAgain:
// Call sayHelloAgain and input the parameter you're using for the name in the sayHello function
return sayHelloAgain(greetingName)
and thirdly, in the documentation, there's a previous function you need to include:
func sayHello(personName: String) -> String {
let greeting = "Hello, " + personName + "!"
return greeting
}
I hope this helps!
Julien Schmitt
2,334 PointsHi Anjali,
Indeed this helped me :)
Thanks !
Anjali Pasupathy
28,883 PointsYou're welcome! (: