the_list = ["a", 2, 3, 1, False, [1, 2, 3]]

# Your code goes below here
the_list.pop(3)
the_list.insert(0, 1)

the_list.remove("a")
del the_list[3]
del the_list[3] 

Keep in mind that when you remove "a", the list size changes. So 2 is now at index 0 etc. There are different ways to do it. :) Hope that helps

There's a simpler way, puzzled me for a while too.

the_list = ["a", 2, 3, 1, False, [1, 2, 3]]

Your code goes below here

the_list.insert(0, the_list.pop(3)) the_list.remove("a") the_list.remove(False) the_list.remove([1, 2, 3]) the_list.extend(range(1, 21))

Dylan's code almost works. However, for some reason it won't remove the last item in the list (figured out by using a simple print function). At first I assumed to had something to do with this item being a list but it doesn't. I tested switching the position of the list and the Boolean value and found that whichever was the last list item was not removed. I can't figure out why. But I do have a pretty easy work around, just straight up delete the last item. I added "del the_list[5]" the line before the for/loop and passed the code challenge. In fact, after figuring out this method succeeded I went back and found that you can just delete them all this way and don't even need the for/loop.

Not exactly quality learning but seeing as treehouse still has no mechanism for actually telling how you were supposed to approach the challenge or even a little mercy for those stuck on a challenge through dozens of failed attempts, I don't exactly feel guilty.

Side note, if anyone does know why Dylan's for/loop doesn't seem to iterate all the way through the list, I'd be interested to know.

I too was really struggling with this one. After working on this for a while, I decided to take it in 2 parts. For the first part, I iterate through 'the_list' and find the indices that I want to remove. I add these indices to a new list called 'removal_index_list'. Then I iterate through the 'removal_index_list' and remove those indices from 'the_list'. There seems to be a bug that happens when you try to remove the item from 'the_list' while you're iterating on it, so seems like you have to do this one in 2 passes.

My solution (which passed):

tempitem = the_list.pop(3) the_list.insert(0, tempitem)

index = 0

removal_index_list = []

index = 0 for item in the_list: if type(item) is str or type(item) is bool or type(item) is list: removal_index_list.append(index) index = index + 1

removal_index_list.reverse()

for indx in removal_index_list: del the_list[indx]

print("final list") print(the_list)

messy_list = ["a", 2, 3, 1, False, [1, 2, 3]]

Your code goes below here

messy_list.pop(3) messy_list.insert(0 , 1) messy_list.remove("a") del messy_list[3] messy_list.remove([1, 2, 3])

i tried all of the above, but i am stl stuck

That is some funky stuff going on, try this:

the_list = ["a", 2, 3, 1, False, [1, 2, 3]]

# Your code goes below here
for item in the_list:
    if type(item) is str or type(item) is bool or type(item) is list:
        the_list.remove(item)

Haven't checked it but it should work

This is what I got:

the_list = ["a", 2, 3, 1, False, [1, 2, 3]]

Your code goes below here

the_list.insert(0, the_list.pop(3))

the_list.remove("a")

del the_list[3]

the_list.remove([1, 2, 3])

It worked after I figured out that del requires square brackets instead of parentheses :)