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JavaScript Node.js Basics (2014) Introduction to Node.js The Console

Posted by himsa devil
himsa devil
Courses Plus Student 297 Points

Use the log method on the console object to print out the name variable.

for the******** ....what this **** means

app.js 
var name = "Andrew";
var details = { favouriteLanguage: "JavaScript", age: 31, children: 2.4 } 
var errorMessage = "Something bad has occurred";

function print(name) {
  var outputDiv = document.getElementById('output');
  outputDiv.innerHTML = name;
}

console.log({ name: "Andrew" });
himsa devil
himsa devil
Courses Plus Student 297 Points

thats what i am doing....this **** is making me crazy

Jason Anders
Jason Anders
Treehouse Moderator 145,860 Points
Jason Anders
Jason Anders
Treehouse Moderator 145,860 Points

TREEHOUSE MODERATOR has edited your answer for appropriate language use in the Community Forum (See Treehouse Terms & Conditions. The Community is a place to connect with other students for help; however, offensive and inappropriate language will not accepted. Yes, coding can be frustrating, but please watch your language used in the Community.

:dizzy:

4 Answers

Thomas Nilsen
Thomas Nilsen
14,957 Points
Thomas Nilsen
Thomas Nilsen
14,957 Points 
console.log(name);                     //Challenge 1
console.dir(details);                    //Challenge 2
console.error(errorMessage);     //Challenge 3
Bashir Orfani
Bashir Orfani
13,170 Points
Bashir Orfani
Bashir Orfani
13,170 Points

here is the answer:

console.log(name); console.dir(details); console.error(errorMessage);

kiki kiki
PLUS
kiki kiki
Courses Plus Student 652 Points
kiki kiki
kiki kiki
Courses Plus Student 652 Points

Answer of challenge 2 is : console.dir(details)

Carlos Lantigua
Carlos Lantigua
5,938 Points
Carlos Lantigua
Carlos Lantigua
5,938 Points

ughhh they purposely put in an error on the last line to make any follow on code not work.. this hurts my soul

const errorMessage = "Something bad has occurred";