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PHP PHP Basics Daily Exercise Program Conditionals

Charles Madureira
Charles Madureira
11,825 Points

Use the variables to display the message


I don't understand why is asking me a variable to display

$studentOneName = 'Dave';
$studentOneGPA = 3.8;

$studentTwoName = 'Treasure';
$studentTwoGPA = 4.0;

//Place your code below this comment
if ($studentOneGPA === 4.0) {
 echo "$studentOneName made the Honor Roll";
} else {
 echo  "$studentOneName has a GPA of $studentOneGPA ";

if ($studentTwoGPA === 4.0) {
 echo "$studentTwoName made the Honor Roll";
} else {
  echo "$studentTwoName has a GPA of $studentTwoName ";

2 Answers

Jennifer Nordell
Jennifer Nordell
Treehouse Teacher

Hi there, Charles Madureira! You are incredibly close on this one. And yes, you are using the variable names so this Bummer message might be a bit confusing. The problem here is that you are using an incorrect variable in a single line.

You wrote:

 echo "$studentTwoName has a GPA of $studentTwoName ";

But you meant:

 echo "$studentTwoName has a GPA of $studentTwoGPA ";

In your version, if Treasure (studentTwoName) had not had a GPA of 4.0, it would have printed out "Treasure has a GPA of Treasure" instead of the GPA.

Hope this helps! :sparkles: