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Python

Posted by Matt Brown
Matt Brown
7,782 Points

Using break in python - where am I wrong?

Challenge: I need you to help me finish my loopy function. Inside of the function, I need a for loop that prints each thing in items. But, if the current thing is the string "STOP", break the loop.

Code:

def loopy(items): for item in items: print(item) if item == "STOP": break

Steven Parker
Steven Parker
242,770 Points
Steven Parker
Steven Parker
242,770 Points

Try formatting your code so the spacing shows up (in Python, indentation is everything).
Use the instructions for code formatting in the Markdown Cheatsheet pop-up below the text entry area. :arrow_heading_down:

3 Answers

Alexander Davison
Alexander Davison
65,469 Points

the problem is you are doing the 'if' conditional stuff AFTER the print. Try putting the 'if' stuff BEFORE the print. Code:

def loopy(items):
    for item in items:
        if item == 'STOP':
            break
        print(item)

Hope that helps :smile:

Go Python!

Nicolas Bassano
Nicolas Bassano
2,125 Points

uff, almost punched the screen with this chalenge.

I thought an else was needed for the chalenge. Even if it's not stated.

Can someone explain why?

Alexander Davison
Alexander Davison
65,469 Points

Hello Nicolas, the reason is because it checks if the item is stop FIRST, and if it is, it will break which will skip everything under it and will stop the loop entirely.

Matt Brown
Matt Brown
7,782 Points

Thank you super helpful!

Steven Parker
Steven Parker
242,770 Points
Steven Parker
Steven Parker
242,770 Points

:point_right: The test for "STOP" (and the break) should come before the print.

Otherwise, the word "STOP" will be printed before the loop ends.

Nicolas Bassano
Nicolas Bassano
2,125 Points
Nicolas Bassano
Nicolas Bassano
2,125 Points

ahaa, got it, no point for an else there.

thanks a lot!!!

Alexander Davison
Alexander Davison
65,469 Points

No problem! :smile:

Alexander Davison
Alexander Davison
65,469 Points

and also, you could use an else if you want to, and it'll still work.