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renhe
10,282 PointsUsing sorted() versus list.sort()
For this task, when I used times.sort() instead of sorted(times) I got the following error: 'NoneType' object is not subscriptable. I was wondering why times.sort() does not work. The code below passed the challenge.
# If you need help, look up datetime.datetime.fromtimestamp()
# Also, remember that you *will not* know how many timestamps
# are coming in.
import datetime
def timestamp_oldest(*args):
times = []
for arg in args:
times.append(datetime.datetime.fromtimestamp(arg))
oldest = sorted(times)
return oldest[0]
1 Answer
Steven Parker
229,732 PointsThe .sort() function does not return a value.
It directly sorts the list you apply it to. But you could do this:
# ...same up through the loop...
times.sort()
return times[0]
renhe
10,282 Pointsrenhe
10,282 PointsThanks for the clarification! Do you know why the following does not work?
Steven Parker
229,732 PointsSteven Parker
229,732 PointsYes, just as I said, it's because the .sort() function does not return a value: