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Allison Guthrie
6,781 PointsUsing .sort(function (a,b)... with the .length method
Hi there, I can't seem to figure the second question out. Right now, I have:
Here's the task:
"Sort the 'saying2' array, on about line 19, so that the words are listed in length order. The shortest first. Use the 'length' property on the strings in the sort function."
Here's my answer: saying2.sort(function (a,b){ saying2.length });
Here's the comment about it not passing:
Bummer! The 'saying2' was 'The,quick,brown,fox,jumped,over,the,lazy,dog's,back' not 'The,fox,the,over,lazy,back,quick,brown,dog's,jumped'.
I know this isn't right, but I can't seem to figure out how to combine both parts of this task. Please help. Thanks so much!
1 Answer

George Kuka
2,673 PointsOk so you're passing in two arguments into the function ~ a & b. These are the arguments that you'll use the length method on to determine how it's sorted.. So the function should look like this...
function( a, b ) { return a.length - b.length; };
The sort function is looking for a -1, 0, or 1 on the return. Here's a link that helped me understand it a bit better.
http://www.javascriptkit.com/javatutors/arraysort.shtml
Allison Guthrie
6,781 PointsAllison Guthrie
6,781 PointsThanks so much, George. Makes sense now. Thanks also for the link. I really appreciate it. :)