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Denis Markus
250 Pointsusing .split() correctly for this 'challenge'. available = "banana split;hot fudge;cherry;malted;black and white"
available = "banana split;hot fudge;cherry;malted;black and white" available = "banana split;hot fudge;cherry;malted;black and white".split() "banana split;hot fudge;cherry;malted;black and white".split()
available = "banana split;hot fudge;cherry;malted;black and white"
available = "banana split;hot fudge;cherry;malted;black and white".split()
"banana split;hot fudge;cherry;malted;black and white".split()
2 Answers
james south
Front End Web Development Techdegree Graduate 33,271 Pointsthe split method returns a list. you call it on the string you want to split up, and (you don't have to) a convenient step would be to store the result in another variable. so myVar = available.split(;). the argument split takes is the delimiter in the original string that separates the elements you want split, so here it is the semicolon. after calling split you have a list of the elements originally separated by semicolons.
Lukas Coffey
20,382 PointsTry available.split(). Then assign that to the menu variable.