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Java Java Basics Getting Started with Java IO

Using the console's printf method, display a message that says, "First name: ", followed by the first name that the user

How should this be written

IO.java
// I have imported java.io.Console for you.  It is a variable called console.
String firstName = console.readLine("Kimberli");
String lastName = console.readLine("Broadus");
String firstName = console.printf("Kimberli");
Rohit Tolawat
Rohit Tolawat
8,277 Points

String firstName = console.readLine("Enter your first name:"); console.printf("First Name: %s \n",firstName);

/* Do the above and I think your issue would be solved */

2 Answers

cm21
cm21
150,854 Points

Hi Kimberli,

1) There's no need to declare firstName again. In fact, the Java compiler won't allow the variable to be declared more than once.

2) You'll need to use a placeholder, known as a formatter, to follow the printf method's syntax rules for telling the Java compiler that you have a string variable you want to print out. You'll want to use the %s string formatter, and after a comma, state which string variable you want to print out.

// I have imported java.io.Console for you.  It is a variable called console.
String firstName = console.readLine("Kimberli");
String lastName = console.readLine("Broadus");
console.printf("First name: %s", firstName);

You'll be writing something similar to that last line for step 4.

Hope this helps!

Thank you, CJ