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Start your free trial###### Heather Stone

5,784 Points# Using the sqrt method in the Math module, assign the value of the square root of 9 to the variable @sqrt.

This should be very simple!

Math::E = @e Math::PI = @PI

I set these variables to these values and the code is accepted, but when I input

Math.sqrt(9) = @sqrt

it says Task 1 is no longer passing. I feel like this should be so easy, so I'm not sure what to do now.

Thanks!

```
@pi = nil
@e = nil
@sqrt = nil
Math::E = @e
Math::PI = @PI
Math.sqrt(9) = @sqrt
```

## 8 Answers

###### Lukas Jones

11,667 PointsI would flip your variable assignments so they look like this

```
@e = Math::E
@PI = Math::PI
@sqrt = Math.sqrt(9)
```

###### jonathan kennedy

Courses Plus Student 9,251 PointsIve tried this every which way and it does not work?????

```
@sqrt = Math.sqrt(9)
Math.sqrt(9) = @sqrt
```

either was should work?????

###### Michael Jasinski

7,427 PointsI have @sqrt = Math.sqrt(9) exactly and will not pass. Just a buggy system!

###### Matthew Delange

26,584 PointsHas anyone passed this Task yet?
I have tried everything and either task one is no longer passing or the `@sqrt`

variable did not have the correct value.

###### MICHAEL P

5,191 PointsThis ends up working:

@sqrt = Math.sqrt(9)

###### Volodymyr Rusynyk

5,725 Pointsstart again from the 1-st task - it will work

###### niloufarsedarati

Courses Plus Student 17,665 PointsThat's funny ! I have the same problem now and I don't know to how figure out this ,,,

```
@pi = nil
@e = nil
@sqrt = nil
module Math
Math::E = @e
Math::PI = @PI
Math.sqrt(9) = @sqrt
end
```

###### Unsubscribed User

48,988 Points```
@pi = nil
@e = nil
@sqrt = nil
Math::E = @e
Math::PI = @pi
@sqrt = Math.sqrt(9)
```