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Sabaa TalalCourses Plus Student 733 Points
using try: function
(You'll probably want to use try and except on this one. You might have to not use the else block, though. Write a function named squared that takes a single argument. If the argument can be converted into an integer, convert it and return the square of the number (num ** 2 or num * num). If the argument cannot be turned into an integer (maybe it's a string of non-numbers?), return the argument multiplied by its length. Look in the file for examples.)
this is the question I am solving, I tried this codes but it did not work, can you help me figure what is wrong with it. sincerely,,
# EXAMPLES # squared(5) would return 25 # squared("2") would return 4 # squared("tim") would return "timtimti def squared(num): try number = int(num) except ValueError: return num*len(num) else: return number**2
Steven Parker225,652 Points
You're close, and your math is all good, but you have some formatting issues:
- the "try" should be on a line by itself
- "try" should be followed by a colon
- "try", "except" and "else" should all be indented (the same amount)