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# using try: function

(You'll probably want to use try and except on this one. You might have to not use the else block, though. Write a function named squared that takes a single argument. If the argument can be converted into an integer, convert it and return the square of the number (num ** 2 or num * num). If the argument cannot be turned into an integer (maybe it's a string of non-numbers?), return the argument multiplied by its length. Look in the file for examples.)

this is the question I am solving, I tried this codes but it did not work, can you help me figure what is wrong with it. sincerely,,

squared.py
```# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimti
def squared(num):
try number = int(num)
except ValueError:
return num*len(num)
else:
return number**2
```

## 1 Answer

You're close, and your math is all good, but you have some formatting issues:

• the "try" should be on a line by itself
• "try" should be followed by a colon
• "try", "except" and "else" should all be indented (the same amount)