Using Uri.parse and setting an Intent

Question

This one has been giving me some trouble. I am basically supposed to take the urls in the mUrls object and make them open in the web browser when clicked. I believe I am somehow supposed to use the 'position' parameter of the onListItemClick method. And then I am supposed to set my Intent with that data. My attempt is the last three lines down at the bottom in the onListItemClick method. I believe the Intent portion is correct, but I do not know how to get the url's from mUrls. If anyone can help it would be appreciated.

""" import android.view.ListView; import android.content.Intent; import android.net.Uri;

public class CustomListActivity extends ListActivity {

protected String[] mUrls = { "http://www.teamtreehouse.com", "http://developer.android.com", "http://www.github.com" };

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_custom_list);

    ArrayAdapter<String> adapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, mUrls);
    setListAdapter(adapter);
}

@Override
protected void onListItemClick(ListView l, View v, int position, long id) {
   super.onListItemClick(l, v, position, id);

  String url = mUrls.getString(position);
  Intent intent = new Intent(Intent.ACTION_VIEW);
  intent.setData(Uri.parse(url));
}

}

Answer 1 · 2014-07-08T18:05:14Z

July 8, 2014 6:05pm

Recall how to get something out of an array.

If you want to get the first item, it'd be mUrls[0]; The position variable gives you an int that is the row position that is clicked. If I click the first row, it'll give me 0, then 1, 2, and so forth.

So to get whatever url is in the row position that I click, I want this code: String url = mUrls[position]; Then your code should be ok, just add startActivity(intent); at the end of your intent code so it actually starts the intent.

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Louis Sankey

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Using Uri.parse and setting an Intent

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Jacob Cho

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Louis Sankey

Louis Sankey