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Python

Posted by Timothy Showler
Timothy Showler
Courses Plus Student 185 Points

ValueError: list.remove(x): x not in list

Ok so I am a little stuck with python .remove()

The entire code is > states = ['ACTIVE',['red', 'green', 'blue'],'CANCELLED','FINISHED',5,]

I have tried to use; states.remove(['ACTIVE','CANCELLED','FINISHED',5]) and no luck, I keep getting

ValueError: list.remove(x): x not in list -- on every attempt I make. Am I doing something wrong?

Tonye Jack
.a{fill-rule:evenodd;}techdegree
Tonye Jack
Full Stack JavaScript Techdegree Student 12,469 Points

first your list doesn't need a comma at the end of it and using a function remove(x) x should be and item in the list and you don't need [] brackets . remove() only takes one argument in this case your specifying 4. better to use del

 states =['ACTIVE', ['red', 'green', 'blue'], 'CANCELLED', 'FINISHED', 5]
 new_list = states.pop(1)
 del states [0:len(states):]

this is a less complicated way to delete multiple items at once.

new_list = ['red', 'green', 'blue']

2 Answers

Joseph Holms
Joseph Holms
5,409 Points
Joseph Holms
Joseph Holms
5,409 Points

Hello Timothy, It looks like the issue you are currently facing is due to the use of brackets with the "remove" command. Please see an example listed below. In this example, is shows only the parentheses used to remove the preferred portion. Please do let me know if I can answer any additional questions.

aList = [123, 'xyz', 'zara', 'abc', 'xyz']; aList.remove('xyz');

Vlad Monea
Vlad Monea
3,394 Points
Vlad Monea
Vlad Monea
3,394 Points

Hello Timothy, list.remove() only takes one parameter. By serving it all the items you want removed as a list you hoped to circumvent that but, in reality, python sees the list you entered as an item of "states" in itself, which is not the case.

You could just try to do states = states[1] --> all that's left are the elements you didn't want removed in the first place.