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JavaScript JavaScript Foundations Numbers Parsing Numbers From Strings

Brian CI
Brian CI
28,971 Points

var j = parseInt("012); different on firefox than chrome?

I am using firefox instead of chrome and with firefox I get j = 12 and not 10 as in the video. Is this cause for concern?

2 Answers

Have a look at the Teachers notes on that video:

"Teacher's Notes

Please note that newer browsers will return 12 for parseInt("012") and not 10. This is because the default second parameter is now 10 for decimal instead of 8 for octal.

Always specify the base if you're parsing a string to maximize compatibility.

parseInt("012", 10); //For decimal parseInt("012", 8); //For octal"

I just tried it using FF and got 12

> var j = parseInt("012");
> j
Brian CI
Brian CI
28,971 Points

Does it match the video in Chrome?