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# Way around this function

I´ve been trying to put it all together, but i had to write the math random 3 times, otherwise it ends up with repeated numbers like 111,111,111 or 15,15,15 which causes black, white and grays divs. Any suggestion?

Thanks

```var html = ´´;
var rgbColor;

function makeColors(){
var color1 =  Math.floor(Math.random() * 256 ) ;
var color2 =  Math.floor(Math.random() * 256 ) ;
var color3 =  Math.floor(Math.random() * 256 ) ;

var color = 'rgb(';
color += color1  + ',';
color += color2  + ',';
color += color3  + ')';
return color;
}

function print(message){
document.write(message);
}

for (var i = 0; i < 10; i++) {

rgbColor = makeColors();
html += '<div style="background-color:' + rgbColor + '"></div>';
}
print(html);
```

If you want 3 different colors, you must use 3 random values, but you can consolidate the process by creating a function that generates a random color value, and then calling it 3 times to get the actual color:

```const rc = _=> Math.floor(Math.random() * 256);
const makeColors = _=> `rgb(\${rc()},\${rc()},\${rc()})`;
```

That's it, the generating random number must be a function. Thank you very much!! This is how it worked for me:

```var html = '';
var rgbColor;

function makeColors(){

let rc = () => {return Math.floor(Math.random() * 256 )};

let  color = `rgb(\${rc()},\${rc()},\${rc()})`;

return color;

};

function print(message){
document.write(message);
}

for (var i = 0; i < 1000; i++) {

rgbColor = makeColors();
html += '<div style="background-color:' + rgbColor + '"></div>';
}
print(html);
```